# SOLUTION: f(h(x))= when f(x) = 2x-1 and h = x+4 I took (2x-1)(x+4) and that gave me 2x^+8x-x-4 which i 2x^+7x-4 but my options for an answer are 2x+3, 2x+7, 7, and 2x^+7x-8 - i dont get a

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: f(h(x))= when f(x) = 2x-1 and h = x+4 I took (2x-1)(x+4) and that gave me 2x^+8x-x-4 which i 2x^+7x-4 but my options for an answer are 2x+3, 2x+7, 7, and 2x^+7x-8 - i dont get a      Log On

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 Click here to see ALL problems on Rational-functions Question 217952: f(h(x))= when f(x) = 2x-1 and h = x+4 I took (2x-1)(x+4) and that gave me 2x^+8x-x-4 which i 2x^+7x-4 but my options for an answer are 2x+3, 2x+7, 7, and 2x^+7x-8 - i dont get any of them and i have been working on this for 2 hours. Can anyone please help me - thank you.Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!the notation is the thing f(h(x)) means put h(x) in place of x in the function f(x) f(h(x)) = 2(h(x)) - 1 = 2(x + 4) - 1 = 2x + 7