SOLUTION: Find the vertical asymptotes of F(x)= (3x+5)/(6x^2-x-2). Would this problem be x=1/2, x=-2/3. or x-1/2, x 2/3 I am not sure about this one. Any help would be greatly appreci

Question 207647This question is from textbook
: Find the vertical asymptotes of F(x)= (3x+5)/(6x^2-x-2).
Would this problem be x=1/2, x=-2/3. or x-1/2, x 2/3
I am not sure about this one. Any help would be greatly appreciated. Thank you for your time and for your help.
This question is from textbook

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
To find the vertical asymptotes, simply set the denominator equal to zero to get . From there, solve for 'x' to find the x values that make the denominator equal to zero. These x values will be the equations of the vertical asymptotes.

If you don't know how to solve, then....

Start with the given equation.

Notice that the quadratic is in the form of where , , and

Let's use the quadratic formula to solve for "x":

Start with the quadratic formula

Plug in , , and

Negate to get .

Square to get .

Multiply to get

Rewrite as

Add to to get

Multiply and to get .

Take the square root of to get .

or Break up the expression.

or Combine like terms.

or Simplify.

So the solutions are or

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Answer:

This means that the vertical asymptotes of are and
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