SOLUTION: ``F(x)=1/5(x+5)^2+8 What is the vertex the line of symmerty what is the maximum/miniumum value of F(x) Is the value of f(-5)=8 maixumum/minimum and how would it look graphed.

Algebra ->  Rational-functions -> SOLUTION: ``F(x)=1/5(x+5)^2+8 What is the vertex the line of symmerty what is the maximum/miniumum value of F(x) Is the value of f(-5)=8 maixumum/minimum and how would it look graphed.       Log On


   

Question 203916: ``F(x)=1/5(x+5)^2+8
What is the vertex
the line of symmerty
what is the maximum/miniumum value of F(x)
Is the value of f(-5)=8 maixumum/minimum
and how would it look graphed.
Please Help, this is the only problem I am stuck on thank you''.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
The given equation f%28x%29+=+%281%2F5%29%28x%2B5%29%5E2%2B8 is in the form:
f%28x%29+=+a%28x-h%29%5E2%2Bk and in this form, the vertex is located at the point (h, k), the line of symmetry is x = h.
So we have:
a+=+%281%2F5%29
h+=+-5
k+=+8
The vertex is at (-5, 8)
The equation of line of symmetry (LOS) is: x+=+-5 and
f%28-5%29+=+8 is a minimum because the parabola opens upward. (positive coefficient of the x%5E2-term).
The graph looks like:
graph%28400%2C400%2C-20%2C5%2C-5%2C20%2C%281%2F5%29%28x%2B5%29%5E2%2B8%29%29