SOLUTION: ``F(x)=1/5(x+5)^2+8 What is the vertex the line of symmerty what is the maximum/miniumum value of F(x) Is the value of f(-5)=8 maixumum/minimum and how would it look graphed.

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Question 203916: ``F(x)=1/5(x+5)^2+8
What is the vertex
the line of symmerty
what is the maximum/miniumum value of F(x)
Is the value of f(-5)=8 maixumum/minimum
and how would it look graphed.
Please Help, this is the only problem I am stuck on thank you''.

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
The given equation is in the form:
and in this form, the vertex is located at the point (h, k), the line of symmetry is x = h.
So we have:



The vertex is at (-5, 8)
The equation of line of symmetry (LOS) is: and
is a minimum because the parabola opens upward. (positive coefficient of the -term).
The graph looks like:

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