# SOLUTION: The width of rectangle is 1 ft less than the length. The area is 6ft^2. find the lenght and the width. width is 2 ft the length 3 ft.

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: The width of rectangle is 1 ft less than the length. The area is 6ft^2. find the lenght and the width. width is 2 ft the length 3 ft.       Log On

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 Question 203079: The width of rectangle is 1 ft less than the length. The area is 6ft^2. find the lenght and the width. width is 2 ft the length 3 ft. Found 2 solutions by dyakobovitch, checkley77:Answer by dyakobovitch(40)   (Show Source): You can put this solution on YOUR website!Width=L-1 Length=L Area=LW=L(L-1)=6 L^2-L-6=0 (L-3)(L+2)=0 So, L=3 [since -2 is an extraneous solution] By substitution, Width=L-1=3-1=2 -- David Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!W=L-1 WL=6 (L-1)L=6 L^2-L=6 L^2-L-6=0 (L-3)(L+2)=0 L-3=0 L=3 IS THE LENGTH OF THE RECTANGLE. W=3-1=2 IS THE WIDTH OF THE RECTANGLE. PROOF: 2*3=6 6=6