SOLUTION: john and peter are 448 meters apart. they start walking towords each other at the same time. peter walks at a speed of 3 m/s and john at 4 m/s. 1. after how many minutes will the

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Question 202309: john and peter are 448 meters apart. they start walking towords each other at the same time. peter walks at a speed of 3 m/s and john at 4 m/s.
1. after how many minutes will they meet?
2. what distance will each have walked when they meet

Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Use the relationship between distance, rate, and time:



Which can be expressed as time as a function of distance and rate as:



Let represent the distance John walked, and then represents the distance that Peter walked. So, using the given rates we can say, with regard to John:



And with regard to Peter:



Since they started at the same time, and the end of both trips is the time that they met, is identical for both equations. That means we can equate the right-hand sides of the two equations:



Solve this equation for . Hint: Cross-multiply, distribute, collect like terms, and then divide by the resulting coefficient on d.

will be the distance that John walked. Subtract this value from 448 to get the distance that Peter walked. That will answer question 2.

Divide the distance John walked by 4 or divide the distance Peter walked by 3 (they are both the same result) to get the number of seconds that will have elapsed when they met. Divide this result by 60 to get the number of minutes for question 1.

John


Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
john and peter are 448 meters apart. they start walking towards each other at the same time. peter walks at a speed of 3 m/s and john at 4 m/s.
1. after how many minutes will they meet?
Peter DATA:
Distance = x meters ; rate = 3 m/s ; time = x/3 seconds
---
John DATA:
Distance = 448-x meters ; rate = 4 m/s ; time = d/r = (448-x)/4 seconds
---
Equation:
Peter time = John time
(448-x)/4 = x/3
4x = 3(448-x)
4x = 3*448 - 3x
7x = 3*448
x = 192 (distance Peter walks)
---
Time required for them to meet:
time = x/3 = 192/3 = 64 seconds = 1 minute 4 seconds
========================================================
2. what distance will each have walked when they meet
John will walk 448-x = 448-192 = 256 meters
====================================================
Cheers,
Stan H.

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