SOLUTION: Please help me solve this equation by finding all zeros: f(x)= x^3-6x^2+4x-24
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Question 196678: Please help me solve this equation by finding all zeros: f(x)= x^3-6x^2+4x-24
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please help me solve this equation by finding all zeros: f(x)= x^3-6x^2+4x-24
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I graphed it and found x=6 is a zero:
Using synthetic division I get:
6)....1....-6....4....-24
.......1.....0.....4...|..0
Quotient: x^2+4
---------------
Other Zeros:
x^2+4 = 0
(x+2i)(x-2i) = 0
x = 2i or x = -2i
======================
Final Answer:
x = 6 or x = 2i or x = -2i
================================
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Recall that the zeros are the values of "x" that make
Start with the given function
Plug in
Rearrange the equation
Group the terms into pairs
Factor the GCF from the first group
Factor the GCF from the second group
Combine like terms.
or Set each factor equal to zero
or Get the constant terms to the right side
or Take the square root of both sides of the first equation.
, or Simplify
So the zeros are , or
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