You can
put this solution on YOUR website!(x+3)/(x-5)(x-2)>0
x cannot be 5 or 2 because there would be division by zero. Therefore 2 and 5 are inflection points and we have to test whether the inequality is >0 on either side of them.
Let x=1: (1+3)/(1-5)(1-2)=1
Let x=3: (3+3)/(3-5)(3-2)=-3
Let x=6: (6+3)/(6-3)(6-2)=3/4
So x(-infinity,2)U(5, infinity) Answer.
.
Ed