SOLUTION: Okay, so I tried doing this problem numerous times and didn't know what to do. -Find All Roots. x^3-13x^2+56x-78 Please And Thank you for your help (:

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Question 193425: Okay, so I tried doing this problem numerous times and didn't know what to do.
-Find All Roots.
x^3-13x^2+56x-78

Please And Thank you for your help (:

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
-Find All Roots.
x^3-13x^2+56x-78
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The only real root is 3.
Divide by (x-3) -->
x^2 - 10x + 26 = 0
Use the quadratic eqn to find the other 2 zeroes.
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -4 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -4 is + or - .

The solution is , or
Here's your graph:

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x = 5+i
x = 5-i

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