SOLUTION: Could you please help me and explain these problems. 1. To determine the number of deer in a game preserve, a conservation catches 545 deer tags them and let them loose. Later, 836
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Question 192775: Could you please help me and explain these problems. 1. To determine the number of deer in a game preserve, a conservation catches 545 deer tags them and let them loose. Later, 836 deer are caught, 209 of them are taged. How many deer are in the preserve? __deer. I do I add 545 and 209 to get the answer to this problem. 2. Lisa can shovel snow from her driveway in 40 mintues. Jim can do the same job in 50 mintues. How long would it take Lisa and Jim to shovel the driveway if they work together. __mintues. Do I do the same as in the frist question. 3. q+7/2/+/q-7/7=7 is this correct No solution since the answer can be only 7
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
I am not sure what you doing here, but this is the way I would do it.
:
1. To determine the number of deer in a game preserve, a conservation catches
545 deer tags them and let them loose. Later, 836 deer are caught, 209 of them
are tagged. How many deer are in the preserve?
:
The ratio of caught deer 209:836, same as 545 is to deer (d) running around
=
cross multiply
209d = 545 * 836
209d = 455620
d =
d = 2180 deer in the preserve
:
:
2. Lisa can shovel snow from her driveway in 40 minutes.
Jim can do the same job in 50 minutes.
How long would it take Lisa and Jim to shovel the driveway if they work together.
:
Let t = time required when they work together
Let the completed job = 1
:
Each will do a fraction of the job that will add up to 1:
+ = 1
Multiply equation by 200 to get rid of the denominators, results:
5t + 4t = 200
9t = 200
t =
t = 22.22 minutes working together
:
:
Check using a calc:
+ = 1
.5555 + .4444 = .9999 ~ 1
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