SOLUTION: So consider the rational function defined f(x)=(x^2-9)/(x+3). For what value of x does the graph exhibit a "hole"?

Question 192418: So consider the rational function defined f(x)=(x^2-9)/(x+3). For what value of x does the graph exhibit a "hole"?
Found 2 solutions by edjones, stanbon:
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
f(x)=(x^2-9)/(x+3)
x=-3 because division by zero is not allowed.
.
Ed

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
So consider the rational function defined f(x)=(x^2-9)/(x+3). For what value of x does the graph exhibit a "hole"?
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f(x) = [(x+3)(x-3)]/[x+3]
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The "hole" is at x=-3 because (x+3) is a factor of the numerator and denominator
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Cheers,
Stan H.
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