SOLUTION: simplify
(n-6)/(n^2+11n+24) / (n+1)/(n+3)
its a double division, i think, the first two problems (n-6)/(n^2+11n+24) is the numerator, and the second two problems are th
Algebra.Com
Question 191957: simplify
(n-6)/(n^2+11n+24) / (n+1)/(n+3)
its a double division, i think, the first two problems (n-6)/(n^2+11n+24) is the numerator, and the second two problems are the denominator
Thank yoou
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression.
Multiply the first fraction by the reciprocal of the second fraction .
Factor to get .
Combine the fractions.
Highlight the common terms.
Cancel out the common terms.
Simplify.
FOIL the denominator
So simplifies to .
In other words, where , , or
RELATED QUESTIONS
Simplify and state restrictions
{{{(n-6)/(n^2+11n+24)}}}{{{"÷"}}}{{{ (n+1)/(n+3)}}}
(answered by Boreal,Edwin McCravy)
Please help me solve:
Simplify the rational expression, if possible.
n^2+2n-24 divided... (answered by MathLover1)
(n^2+5n+6/n^2+7n+12)(n^2+9n+20/n^2+11n+30)=... (answered by Earlsdon,jim_thompson5910,jsmallt9)
simplify the complex fraction... (answered by Alan3354)
11n-6(n-9)=-9(1-n)+11 (answered by )
n square... (answered by varun)
factor each completely:... (answered by jim_thompson5910)
I've been working through factoring polynomials and have solved the following as such;... (answered by stanbon)
Solve... (answered by Alan3354)