SOLUTION: Subtract and simplify if possible (b^2-2b-8)/(b^2+b-2) - 6/(b-1) Thankk youu :)

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Question 191956: Subtract and simplify if possible

(b^2-2b-8)/(b^2+b-2) - 6/(b-1)




Thankk youu :)
Answer by jim_thompson5910(21685) About Me  (Show Source):
You can put this solution on YOUR website!
%28b%5E2-2b-8%29%2F%28b%5E2%2Bb-2%29+-+6%2F%28b-1%29 Start with the given expression.


%28%28b%2B2%29%28b-4%29%29%2F%28b%5E2%2Bb-2%29+-+6%2F%28b-1%29 Factor the first numerator


%28%28b%2B2%29%28b-4%29%29%2F%28%28b%2B2%29%28b-1%29%29+-+6%2F%28b-1%29 Factor the first denominator


%28highlight%28%28b%2B2%29%29%28b-4%29%29%2F%28highlight%28%28b%2B2%29%29%28b-1%29%29+-+6%2F%28b-1%29 Highlight the common terms.


%28cross%28%28b%2B2%29%29%28b-4%29%29%2F%28cross%28%28b%2B2%29%29%28b-1%29%29+-+6%2F%28b-1%29 Cancel out the common terms.


%28b-4%29%2F%28b-1%29-6%2F%28b-1%29 Simplify


Since the denominators are equal, we can combine the fractions


%28b-4-6%29%2F%28b-1%29 Combine the fractions


%28b-10%29%2F%28b-1%29 Subtract


So %28b%5E2-2b-8%29%2F%28b%5E2%2Bb-2%29+-+6%2F%28b-1%29=%28b-10%29%2F%28b-1%29 where b%3C%3E-2 or b%3C%3E1