SOLUTION: a) find the y-int., the equation of the axis of symmetry, and the x-coordinate of the vertex b)make a table of values that includes the vertex c)use this information to graph the

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Question 181670This question is from textbook Algebra 2
: a) find the y-int., the equation of the axis of symmetry, and the x-coordinate of the vertex
b)make a table of values that includes the vertex
c)use this information to graph the function
f(x)=x^2-x+5/4 This question is from textbook Algebra 2

Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website!

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vertex is (,)
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axis of symmetry is x=1/2
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y intercept is found by setting x to zero y=0^2-0+5/4=5/4
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y intercept is (0,5/4)
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for b) and c) just plug in values of x and solve for y for as many points as you want
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we already know that for x=0 y=5/4(the y intercept
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we also know that for x=1/2 y=1
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try more such as x=2--->y(2)^2-2+5/4=13/4
try some negative values, x=-1--->y=(-1)^2-(-1)+5/4=13/4
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interesting both the same value but this makes sense, since vertex is at x=1/2
x=2 and x=-1 are equal distances from 1/2
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hope that helps
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oh here is the graph:
no x intercepts on this parabola