SOLUTION: I need assistance in figuring out the following:
{{{8sqrt(2)(sqrt(8)-3sqrt(2)+7sqrt(32))}}}
I have an algebra test tomorrow and nearly no one in my class really understands
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Question 176969: I need assistance in figuring out the following:
I have an algebra test tomorrow and nearly no one in my class really understands the math material we are being tested on, so this would be extremely helpful and I would be veryyyyyyyy grateful for any help!
Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
8sqrt(2)(sqrt(8)-3sqrt(2)+7sqrt(32)
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Rule: sqrt(AB) = sqrt(A)*sqrt(B)
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= 8 sqrt(16) - 3sqrt(2) + 7sqrt(16)*sqrt(2)
= 8*4 - 3sqrt(2) + 7*4*sqrt(2)
= 32 - 3sqrt(2) + 28sqrt(2)
= 32 + 25sqrt(2)
---------------------
Cheers,
Stan H.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Evaluate:
Ok, the key thing here is to get all of the radicands (the numbers inside of the square root symbols) to = 2, if possible. Well, since you know that 8 and 32 are multiples of 2 this is possible. So here we go, step-by-step!
Now, so you can move that outside of the radical but leave the 2 inside. And, so you can move that outside of the radical leaving the 2 inside:
Multiply the 7*4 = 28
In the second set of parentheses, collect all of the 's together.
Finally, perform the indicated multiplication, do the numbers first (8*27 = 216) then the radicals ( to get:
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