# SOLUTION: Find the inverse of A= (matrix) -3....1 -5....5 if it exists.

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 Question 174766This question is from textbook Saxon Algebra 2 : Find the inverse of A= (matrix) -3....1 -5....5 if it exists.This question is from textbook Saxon Algebra 2 Answer by KnightOwlTutor(293)   (Show Source): You can put this solution on YOUR website!We know that the matrix has an inverse because the determinant is not equal to zero [-3 1] [-5 5] [a b] [c d] To calculate the determinant ad-bc in this case -15+5=-10 Any Matrix inverse =1/ad-bc[d -b] [-c a] -1/10[5 -1] [5 -3] To double check multiply the matrices together and see if you come up with the identity matrix. [-3 1]-1/10[5 -1] [-5 5] [5 -3] -15+5 3+3 -1/10[-10 0] -25+25 5-15 -1/10[0 -10] [1 0] [0 1] is the identity matrix