SOLUTION: solve the equation: watch for extraneous solutions: 5 = y+7 +1 y-3 2y-6

Question 174643: solve the equation: watch for extraneous solutions:
5 = y+7 +1
y-3 2y-6
Answer by nycsub_teacher(90) (Show Source): You can put this solution on YOUR website!
This is what you stated:
Solve the equation: watch for extraneous solutions:
5 = y+7 +1
y-3 2y-6
Now, y - 3 2y - 6 does not make sense.
There is a missing equal sign.
Where does the equal sign go in the case of y-3 2y-6?
Write back and I'll be able to complete this question for you.
==============================================================
I received your e-mail.
I'm sorry but you are not clear in your expression.

Do you want to solve for y?

Here is the fractional equation that I made based on what you said:

[5/(y - 3)] = (y + 7)/(2y - 6)

Is this what you meant to type?

Where does 1 belong in your equation?

If this is what you need solved, then write back.

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