SOLUTION: I don't know how to type this, so I'll try to explain it. Square root symbol, with 6 outside (but inside the little section), and inside the square root is another square root sym

Question 174247: I don't know how to type this, so I'll try to explain it.
Square root symbol, with 6 outside (but inside the little section), and inside the square root is another square root symbol. Inside this second square root symbol is a 2. Now subtract from that: square root with 12 inside the little part, and inside the square root is 2 with exponent of 13.
Hope this makes sense.
Thanks!
Found 2 solutions by ilana, jim_thompson5910:
Answer by ilana(307) (Show Source): You can put this solution on YOUR website!
So I believe you would say this as "the sixth root of the square root of 2 minus the twelfth root of 2 to the thirteenth power". Are you supposed to estimate this using a calculator? If not, I think the most you can simplify it is 2^(1/12) - 2^(13/12). You can do that because, for instance, the square root of 2 is 2^(1/2). So "the sixth root of the square root of 2" is (the square root of 2)^(1/6), which is (2^(1/2))^(1/6). So you multiply the exponents and get 2^1/12. Then you work similarly with the second part.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Is the expression ???

Start with the given expression

Break up to

Break up the exponent (see note below)

Break up the square root (see note below).

Take the 12th root of to get 2 (see note below).

Convert from radical notation to exponential notation. So

Convert from radical notation to exponential notation. So

Convert from radical notation to exponential notation. So

Multiply the exponents and to get

Take note that the GCF is

Factor out the GCF

Subtract

Convert from exponential notation to radical notation. So

Rearrange the terms.

So (Note: the right side reads the negative 12th root of 2)

Notes:

I used the following identities to simplify the expression:

1)

2)

3)
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