SOLUTION: (m+3)/(m^2+5m-14)+(3m+8)/(m^2+8m+7)
Algebra.Com
Question 173862: (m+3)/(m^2+5m-14)+(3m+8)/(m^2+8m+7)
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(m+3)/(m^2+5m-14)+(3m+8)/(m^2+8m+7)
(m+3)/(m+7)(m-2)+(3m+8)/(m+7)(m+1)
[(m+3)(m+1)+(3m+8)(m-2)]/(m+7)(m-2)(m+1)
[m^2+4m+3+m^2+2m-16]/(m+7)(m-2)(m+1)
[2m^2+6m-13]/(m+7)(m-2)(m+1)
RELATED QUESTIONS
7[3m - (m + 2)] > -6(m -... (answered by stanbon)
(5m^4+m^3-3m^2-m-2) /... (answered by friesr)
(5m-2)(m+3) (answered by checkley79,Alan3354)
M/m^2-4+2/m^2+5m+6-3m/m^2+m-6 (answered by ikleyn)
m^2 - 5m - 14 = 0
(answered by Stitch,Deysha)
Solve for m... (answered by checkley71)
{ { { m^2+5m/m^2-25 / m^2-3m-18/m^2-11m+30 } }... (answered by sdmmadam@yahoo.com)
I am confused about this problem I'm not sure if its right.
8/2m+1 - 1/m-2 = 5/2m+1
(answered by sarah_adam)