SOLUTION: thi is actually a problem from a exam. It is my study for my final but i got it wrong. (125x^6y)3\4 /(8x^2y^4)-1\3 This what I did, (5x^2y^3)2=25x^4y^6 that's what I got for

Question 173157This question is from textbook beginning and intermediate algebra
: thi is actually a problem from a exam. It is my study for my final but i got it wrong. (125x^6y)3\4 /(8x^2y^4)-1\3
This what I did, (5x^2y^3)2=25x^4y^6 that's what I got for my first answer.
for the bottom fraction I did the following: 1/(8x^2y^4)1/3 My aswer was 25x^4y^6/2x^2/3y^4/3 but the answer was 25x^10/3 all over 2y^2/3 please help,i do not know how to get that answer. On the bottom equation I did not know what to do, because the Index was a negative one over 3. Pleas help is for my final. thank you. This question is from textbook beginning and intermediate algebra

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Question: Is the 3\4 & the -1\3 multipliers or exponents?????
Clarify & resubmit.
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