SOLUTION: How would you find the exact coordinates of the vertex for the following quadration function? {{{y=-x(1/2x-12)-1/10}}} Thank you!

Question 168792: How would you find the exact coordinates of the vertex for the following quadration function?

Thank you!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y=-x(1/2x-12)-1/10
y = (1/2)x^2 - 12x - (1/10)
----------------------------
The vertex will occur when x = -b/2a
x = 12/(2(1/2)) = 12
f(12) = (1/2)(12^2) -12*12 - (1/10)
f(12) = 72 - 144 - (1/10)
f(12) = -72.1
-------------------
Vertex: (12 , -72.1)
==========================
Cheers,
Stan H.
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