You can
put this solution on YOUR website!If the graph crosses the x axis at x=-2, then it has a single root (zero) at x= -2, and so there must be a factor of (x-2).
If it bounces off the x axis at x= 2, then there must be a double root (zero) at x=2, and there must be a factor of (x-2)^2.
This would be f(x) = c(x+2)(x-2)^2, where c is some number yet to be determined.
If you said the graph crosses the y-axis at 2, then
f(0) = c*(2)*(-2)^2 = 2
8c = 2, so c= 1/4.
See if this is the graph:
R^2 at SCC