SOLUTION: I really need help on these two questions. Graph: 1. 16x^2+9y^2=144 2. x^2/9-(y+2)^2/9=1 I don't understand how to do these. I have to show my work. PLEASE HELP!!! T

Question 167394: I really need help on these two questions.
Graph: 1. 16x^2+9y^2=144
2. x^2/9-(y+2)^2/9=1
I don't understand how to do these. I have to show my work.
PLEASE HELP!!!
Thanks
Answer by KnightOwlTutor(293) (Show Source): You can put this solution on YOUR website!
The first equation is an ellipse. This is an example of a conic section.
The first step is to divide each term by 144. The equation now becomes x^2/9+y^2/16=1
Make y=0 so that you can determine where the x intercets are on the x axis
what 2 numbers squared make the equation =1? It would be + or -3. Make dots on the x axis at these two points on the axis. Then make x=0 what two values make the equation =1 + or -4. These are your y intercepts. Connect the together to form an oval. A circle is a special type of an ellipse.
The second equation is a hyperbola
x^2/9-(y+2)^2/9=1
Again make y=0
x= + or - 3. Plot these points.
the y has no value but they are the limits of the equation.
Draw two dashed lines at y= +3 and at y=-3 straight across the graph. Make a horseshoe graph at x=+3 and x=-3 but never touching the two dashed lines. This is the vertex of the graph at each side. Therefore you have two horseshoe graph going to infinity in opposite directions.

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