SOLUTION: I've been working on this problem for 2 hours, and I would like some help. I need to "multiply and divide" (-3mn)^2*64(m^2n)^3 over (16m^2n^4(mn^2)^3 divided by 24(m^2n^2)^4 ov

Question 164267This question is from textbook Algebra for college Students
: I've been working on this problem for 2 hours, and I would like some help.
I need to "multiply and divide"
(-3mn)^2*64(m^2n)^3 over (16m^2n^4(mn^2)^3 divided by 24(m^2n^2)^4 over (3m^2n^3)^2
the answer is 27/2mn^7 but I can't figure out how to get there. This question is from textbook Algebra for college Students

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
((-3mn)^2*64(m^2n)^3)/(16m^2n^4)*(mn^2)^3(OVER)24(m^2n^2)^4/(3m^2n^3)^2
Let's deal with the first part first (out to the "over"):
((-3mn)^2*64(m^2n)^3)/(16m^2n^4)*(mn^2)^3=
(9m2^2n^2)*64(m^6n^3)/(16m^2n^4)(m^3n^6)=
(576m^8n^5)/(16m^5n^10)=
36m^3/n^5-------------------------------first part
Next, the part after the "over"
24(m^2n^2)^4/(3m^2n^3)^2=
(24m^8n^8)/(9m4n^6)=
8m^4n^2/3---------------------------second part
Now, we'll put the first part and second part back together
36m^3/n^5 over 8m^4n^2/3 multiply numerator and denominator by 3/8m^4n^2 ( this will make the denominator of the complex fraction equal to 1 and thus get rid of the complex fraction):
(36m^3/n^5)*(3/8m^4n^2) over 1=
(108m^3/(8m4n^7)=
27/2mn^7----------------------------ans
Easy to make a mistake on this one!!!!!!!!

Hope this helps---ptaylor

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