SOLUTION: I submitted the following problems for some help. I got no response and wanted to try again. If someone could help me I would be thankful.find the axis of symmetry and the vertex f

Question 160762: I submitted the following problems for some help. I got no response and wanted to try again. If someone could help me I would be thankful.find the axis of symmetry and the vertex from each parabolic function. A. y=2x^2 -24x+22 B.y=x^2-3x-5
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
read this --> http://www.regentsprep.org/Regents/Math/conics/LPara.htm
Parabolas are of the form: y = ax^2 + bx + c
If a is positive, the parabola opens upward and has a minimum point.
The axis of symmetry is
x = (-b)/2a

If a is negative, the parabola opens downward and has a maximum point.
The axis of symmetry is
x = (-b)/2a.
Once you have the axis, use that value of x to find the vertex.

1)
Since a is positive, use
b is -24, so -b is 24. a is 2

Now solve for y when x=6

So the vertex is (6,-50)

You can do the second one using the same method

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