SOLUTION: Consider triangle ABC in the plane where A=(-1,15) B=(-6,8) C=(-27,23) Find the lengths of the sides of the triangle: AB= BC= AC=

Question 160205: Consider triangle ABC in the plane where
A=(-1,15)
B=(-6,8)
C=(-27,23)

Find the lengths of the sides of the triangle:
AB=
BC=
AC=

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
A=(-1,15)
B=(-6,8)
C=(-27,23)
AB^2=(6-1)^2+(15-8)^2=5^2+7^2=25+49=74
AB=SQRT74=8.6 ANSWER.
BC^2=(27-6)^2+(23-8)^2=21^2+15^2=441+225=666
BC=SQRT666=25.8 ANSWER.
AC^2=(27-1)^2+(23-15)^2=26^2+8^2=676+64=740
AC=SQRT740=27.2 ANSWER.
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