SOLUTION: Find an equation of the circle with center at(-8,7) and passing through(1,-4) in the form of {{{(x-a)^2+(y-B)^2=C}}} where A,B,C are constant. Then A= B= C= Ive alread

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Question 160196: Find an equation of the circle with center at(-8,7) and passing through(1,-4) in the form of where A,B,C are constant. Then
A=
B=
C=
Ive already have the answers for A B they are -8,7 I just how to find C if the radius is not provided
Found 2 solutions by Edwin McCravy, nerdybill:
Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!
Find an equation of the circle with center at(-8,7) and passing through (1,-4) in the form of where A,B,C are constant. Then
A=
B=
C=
Ive already have the answers for A, B they are -8,7. I just
want to know how to find C if the radius is not provided.

So instead of:



write





Think now: What haven't you used that was given?

Answer:  You haven't used this: "passing through (1,-4)"

So that means if you substitute (x,y) = (1,-4), the equation
must be true.  So let's substitute that:








So write  for 



and you're done. The radius is .

Edwin
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
Find an equation of the circle with center at(-8,7) and passing through(1,-4) in the form of where A,B,C are constant.
Then
A= -8
B= 7
C=
.
Recapping you have the center and you're given a point (1, -4) -- simply plug it in and solve for C:





.
A= -8
B= 7
C= 202
and
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