SOLUTION: Would you be able to do me a big favor and see if these problems are correct? #1: 5/x+3 = 3/x-1 (x+3)(x-1). 5/x+3 = (x+3)(x-1) 5(x-1) = 3(x+3) 5x-5 = 3x+9 2x-

Question 159589: Would you be able to do me a big favor and see if these problems are correct?
#1:
5/x+3 = 3/x-1
(x+3)(x-1). 5/x+3 = (x+3)(x-1)
5(x-1) = 3(x+3)
5x-5 = 3x+9
2x-5 = 9
2x/2 = 14/2
x = 7

#2
x/2x^2 - x-1 = 3/x^2 - 1 + 3/2x+1
x/(2x+1)(x-1) = 3/(x+1)(x-1) + 3/2x+1
x/(2x+1)(x-1)(x+1) = 3/(2x+1)(x-1)(x+1) + 3/(2x+1)(x-1)(x+1)
x(x+1) = 3(2x+1) + 3(x+1)(x-1)
x^2 + x = 3x+3 + 3(x^2-x+x-1)
x^2 + x = 3x+3 + 3x^2-3
x^2 + x = 3x^2 + 3x
(x+1)(x-1) = 3x(x+1)
x-1 = 3x
-1 = 2x
x = -1/2
Thanks for you help! Paul

Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
#1 problem is ok but second one is wrong

or

RELATED QUESTIONS
#6. 2(3x-1)= 4(x+2) #7. 3(x-5)=210 If you solve both of these, I will be extremely... (answered by Alan3354)

These problems have me stumped, any help would be greatly appreciated! 1. solve for x: (answered by stanbon)

Are you able to help me please: Solve for X 1. ((4x+3)/(2x-1))=2/5 2.... (answered by ankor@dixie-net.com)

These are on exponentials with logs; in case stan happens to see this, thanks alot for... (answered by stanbon)

por favor necesito la solucion a este problema: (1/5 x + 1/3) (1/5 x - 1/3) (answered by josgarithmetic)

Factorise these completely. x(x+1)(x+3)(x+5)-x(x+3)(x+5) (answered by stanbon)

Hi I need help with adding and subtracting with unlike denominators. I have a couple... (answered by checkley75)

x-1 x+5 --- = --- 3... (answered by checkley77)

(x-1)(x+3)=5 (answered by Fombitz)