SOLUTION: 2(n^2 - 20)+17n= -10n^2
Algebra.Com
Question 155542:  2(n^2 - 20)+17n= -10n^2 
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
 2(n^2 - 20)+17n= -10n^2
2n^2-40+17n+10n^2=0
12n^2+17n-40=0
(3n+8)(4n-5)=0
3n+8=0
3n=-8
n=-8/3 answer.
4n-5=0
4n=5
n=5/4 answer. 
RELATED QUESTIONS
state the excluded values for the following expression. then simplify the expression.... (answered by josgarithmetic,ikleyn,rothauserc)
n^2-10n-24 (answered by jim_thompson5910)
8n-2>17n+9 (answered by ReadingBoosters)
5n^2 + 10n +... (answered by tommyt3rd)
5(n+2)=... (answered by Fombitz)
Evaluate 3n^2-10n-9, given... (answered by MathLover1,Theo)
-7m-10n when m=-2 and n... (answered by solver91311)
-10n^2+35n=0
 (answered by xdragonfight)
Can you please assist me in the following: A number is ten times the sum of its digits.... (answered by stanbon,checkley75,josmiceli)