SOLUTION: Please help me solve this problem on functions: 1. Graph the function f(x)= -3x+7. Label the axes and the line with its equation. Thank you so much!

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Question 152926: Please help me solve this problem on functions:
1. Graph the function f(x)= -3x+7. Label the axes and the line with its equation.
Thank you so much!

Answer by jim_thompson5910(21685) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at y=-3x%2B7 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-3 and the y-intercept is b=7


Since b=7 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

drawing%28500%2C500%2C-10%2C10%2C-10%2C10%2C%0D%0A++grid%281%29%2C%0D%0A++blue%28circle%280%2C7%2C.1%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.12%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.15%29%29%0D%0A%29


Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is -3, this means:

rise%2Frun=-3%2F1


which shows us that the rise is -3 and the run is 1. This means that to go from point to point, we can go down 3 and over 1



So starting at , go down 3 units
drawing%28500%2C500%2C-10%2C10%2C-10%2C10%2C%0D%0A++grid%281%29%2C%0D%0A++blue%28circle%280%2C7%2C.1%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.12%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.15%29%29%2C%0D%0A++blue%28arc%280%2C7%2B%28-3%2F2%29%2C2%2C-3%2C90%2C270%29%29%0D%0A%29

and to the right 1 unit to get to the next point
drawing%28500%2C500%2C-10%2C10%2C-10%2C10%2C%0D%0A++grid%281%29%2C%0D%0A++blue%28circle%280%2C7%2C.1%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.12%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.15%29%29%2C%0D%0A++blue%28circle%281%2C4%2C.15%2C1.5%29%29%2C%0D%0A++blue%28circle%281%2C4%2C.1%2C1.5%29%29%2C%0D%0A++blue%28arc%280%2C7%2B%28-3%2F2%29%2C2%2C-3%2C90%2C270%29%29%2C%0D%0A++blue%28arc%28%281%2F2%29%2C4%2C1%2C2%2C+0%2C180%29%29%0D%0A%29


Now draw a line through these points to graph y=-3x%2B7

drawing%28500%2C500%2C-10%2C10%2C-10%2C10%2C%0D%0A++grid%281%29%2C%0D%0A++graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-3x%2B7%29%2C%0D%0A++blue%28circle%280%2C7%2C.1%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.12%29%29%2C%0D%0A++blue%28circle%280%2C7%2C.15%29%29%2C%0D%0A++blue%28circle%281%2C4%2C.15%2C1.5%29%29%2C%0D%0A++blue%28circle%281%2C4%2C.1%2C1.5%29%29%2C%0D%0A++blue%28arc%280%2C7%2B%28-3%2F2%29%2C2%2C-3%2C90%2C270%29%29%2C%0D%0A++blue%28arc%28%281%2F2%29%2C4%2C1%2C2%2C+0%2C180%29%29%0D%0A%29 So this is the graph of y=-3x%2B7 through the points and