SOLUTION: Find an equation of a line through (1,-3) that is perpendicular to 5x+2y=14

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Question 151049: Find an equation of a line through (1,-3) that is perpendicular to 5x+2y=14
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
5x+2y=14
2y=-5x+14
y=-5x/2+14/2
y=-5x/2+7 (red line) with a slope=-5/2
the perpendicular line has a slope of 2/5 through (1,-3)
Y=mX+b
-3=2/5*1+b
-3=2/5+b
b=-3-2/5
b=(-13-2)/5
b=-15/5
b=-3 for the y intercept for this line with a slope=2/5
y=2x/5-3 (green line)
+graph%28+300%2C+300%2C+-6%2C+8%2C+-6%2C+8%2C+-5x%2F2+%2B7%2C+2x%2F5+-3%29+ (graph 300x300 pixels, x from -6 to 8, y from -6 to 8, of TWO functions -5x/2 +7 and 2x/5 -3).