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put this solution on YOUR website!a bird species in danger of extinction has a population that is decreasing (A=A(base0)e^kt). five years ago the population was at 1400 and today only 1000 are still alive. once the population drops below 100, the situation is irreversible. When will this happen?
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A(t) = A(o) e^(kt)
Find "k":
1000 = 1400 e^(k*5)
(5/7) = e^(5k)
Take the ln to get:
5k = ln (5/7)
5k = -0.3365
k = -0.06729
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Equation: A(t) = A(o) e^(-0.06729t)
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When will the population be 100?
100 = 1000 e^(-0.06729t)
0.10 = e^(-0.06729t)
-0.06729t = ln(0.10)
t = 31.22 years from 5 yrs. ago
OR
26.22 years from NOW
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Cheers,
Stan H.
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