SOLUTION: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a fo

Question 150309: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force?
I don't know what formula that would be to use... I don't know how to approach this task...
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
a formula is not needed __ this is a proportional problem __ k is the constant of proportionality

3600=[k*1800*20^2]/600 __ 3600=k*1200 __ dividing by 1200 __ 3=k

f=[3*1800*50^2]/570 __ f=23684
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