SOLUTION: Multiply: ((3x^(2/3)) + 2)^2
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Question 148115: Multiply: ((3x^(2/3)) + 2)^2
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
^{2})
Start with the given expression.
\left(3x^{\frac{2}{3}}+2\right))
Expand. Remember,
\left(3x^{\frac{2}{3}\right) + \left(3x^{\frac{2}{3}\right)\left(2\right) + \left(2\right)\left(3x^{\frac{2}{3}\right)+ \left(2\right)\left(2\right))
Foil.
\left(2\right) + \left(2\right)\left(3x^{\frac{2}{3}\right)+ \left(2\right)\left(2\right))
Multiply 
and to get \left(3x^{\frac{2}{3}\right)=\left(3*3\right)x^{\frac{2}{3}+\frac{2}{3}}=9x^{\frac{4}{3}})
\left(2\right))
Multiply and 
to get 
. Note: this happens twice since the multiplication order does not matter.
Multiply and to get 
.
Combine like terms.
So FOILs and multiplies to
In other words, ^{2}=9x^{\frac{4}{3}} +12x^{\frac{2}{3}} +4)
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