SOLUTION: How do you graph a circle with the equation 3x^2 + 3y^2 =27

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: How do you graph a circle with the equation 3x^2 + 3y^2 =27      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 144315: How do you graph a circle with the equation 3x^2 + 3y^2 =27
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(21605) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2+%2B+3y%5E2+=27
Divide by 3--> x%5E2+%2B+y%5E2+=+9
That's a circle of radius 3 about the origin.

Answer by stanbon(48564) About Me  (Show Source):
You can put this solution on YOUR website!
How do you graph a circle with the equation 3x^2 + 3y^2 =27
----------------
Divide thru by 3 to get:
x^2 + y^2 = 9
Circle with center at (0,0) and radius = 3
============
Cheers,
Stan H.