SOLUTION: how do I solve this problem for radical equations.
1. (x-2)to the 1/3 power=5 Check for extraneous solution.
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1. (x-2)to the 1/3 power=5 Check for extraneous solution.
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Question 144177: how do I solve this problem for radical equations.
1. (x-2)to the 1/3 power=5 Check for extraneous solution. Answer by stanbon(48558) (Show Source):
You can put this solution on YOUR website! (x-2)to the 1/3 power=5
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(x-2)^(1/3) = 5
Cube both sides to get:
x-2 = 125
x = 127
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Cheers,
Stan H.
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