SOLUTION: how do I solve this problem for radical equations. 1. (x-2)to the 1/3 power=5 Check for extraneous solution.

SOLUTION: how do I solve this problem for radical equations. 1. (x-2)to the 1/3 power=5 Check for extraneous solution.

Algebra.Com

Question 144177: how do I solve this problem for radical equations.
1. (x-2)to the 1/3 power=5 Check for extraneous solution.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(x-2)to the 1/3 power=5
-----------
(x-2)^(1/3) = 5
Cube both sides to get:
x-2 = 125
x = 127
============
Cheers,
Stan H.
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