SOLUTION: I am having trouble with this problem: I have to graph f(x)=a^3/x^2+a^2 if a=4 It would be so cool if someone could help me out on this one. Thanks!

Question 142514: I am having trouble with this problem:
I have to graph f(x)=a^3/x^2+a^2 if a=4
It would be so cool if someone could help me out on this one. Thanks!
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!

If a=4, There are NO ASYMPTOTES and NO ZEROS!!

Plot a few points:
If x=0, then f(x)=4
If x= 1, then f(x) =64/5=12.8
If x=-1, then f(x) = 64/5=12.8
If x=2, then f(x) = 64/8=8
If x=-2, then f(x) = 64/8=8
If x=4, then f(x) = 64/32=2
If x=-4, then f(x) = 64/32=2

R^2
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