SOLUTION: Here's my problem: f(x)=-3/(x-2)^2 I need to graph it. Thanks for the help!

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Question 142512: Here's my problem:
f(x)=-3/(x-2)^2 I need to graph it.
Thanks for the help!
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=-3%2F%28x-2%29%5E2 BTW, are you allowed to use a graphing calculator on this???

First notice the vertical asymptote at x =2. The best points to plot will be "close" to 2, like x=0, x=1, x=3, and x=4.

If x=0, f(x)= -3/4
If x=1, f(x) = -3/1=-3
If x=3, f(x) = -3/1=-3
If x=4, f(x) = -3/4

It should look like this:
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C+-3%2F%28x-2%29%5E2%29+

R^2