SOLUTION: a pickup can travel 300 miles in the same time that a car going 10 miles per hour faster can travel 350 miles. How fast is the car traveling?

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distance equals rate times time, or , so

rate of the car: r (I chose the car's rate to be r rather than the pickup's rate because the question asks for the car's rate)
distance for the car: 350

rate of the pickup: r - 10 (the pickup is going 10 mph slower)
distance for the pickup: 300




time for the pickup:
time for the car:

But the time for the pickup and car are the same, so:



Cross multiply, collect like terms, and solve for r