SOLUTION: Let f(x)=x+1 and g(x)=6 /x+1 Find (f*g)(1) Here is what I have, but it seems to be incorrect. Can you please let me know where I've gone wrong? f=1+1 and g=6/1+1 f=2 and g

Algebra ->  Rational-functions -> SOLUTION: Let f(x)=x+1 and g(x)=6 /x+1 Find (f*g)(1) Here is what I have, but it seems to be incorrect. Can you please let me know where I've gone wrong? f=1+1 and g=6/1+1 f=2 and g      Log On


   

Question 133538This question is from textbook College algebra
: Let f(x)=x+1 and g(x)=6 /x+1
Find (f*g)(1)
Here is what I have, but it seems to be incorrect. Can you please let me know where I've gone wrong?
f=1+1 and g=6/1+1
f=2 and g=6/2
f=2 and g=3
(2*3)=6
This is how I completed this one, but when I took my test, six was not the correct answer. Unfortunately, the correct answer is not given. I am curious to see what I did wrong. This question is from textbook College algebra

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
I think the problem is aksing for (f(g(x)) at the value x =1.
What you need to do is take the function g(x) and use that as the independent variable in f(x). As follows:
f%28x%29+=+x%2B1
g%28x%29+=+6%2F%28x%2B1%29+
Now put the value of g(x) as the independent variable in f(x):
f%28g%28x%29%29+=+%286%2F%28x%2B1%29%29+%2B+1+
Now you can either solve for f(g(x)) and then sub in 1, or just sub in one and solve. Let's sub in 1:
f%28g%281%29%29+=+%286%2F%281%2B1%29%29+%2B+1+
f%28g%281%29%29+=+%286%2F2%29+%2B+1+
f%28g%281%29%29+=+3+%2B+1+
f%28g%28x%29%29+=+4+
For your info, generally the function f(g(x)) is written as (fog(x))