SOLUTION: How do you solve this so I can understand f(x)=-2x^2+2x+6
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Question 131835: How do you solve this so I can understand f(x)=-2x^2+2x+6
Found 3 solutions by stanbon, TakeATuition.com, edjones:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you solve this so I can understand f(x)=-2x^2+2x+6
You cannot "solve" it when you have two variables.
Maybe this is what you mean.
-2x^2+2x+6 = 0
-2(x^2-x-3) = 0
Divide thru by -2 to get:
x^2-x-3 = 0
Now use the quadratic formula to get:
x = [1 +- sqrt(1 -4*-3)]/2
x = [1 +- sqrt(13)]/2
x = (1+sqrt(13)]/2 or x = (1-sqrt(13))/2
==========================
Cheers,
Stan H.
Answer by TakeATuition.com(57) (Show Source): You can put this solution on YOUR website!
SOLUTION -
2x(x+3)-2(x+3)=0
(x+3)(2x-2)=0
x+3=0
x=-3
2x-2=0
2x=2
=
x=1
FOR MORE HELP VISIT :www.TakeATuition.com
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
f(x)=-2x^2+2x+6
-2(x^2-x-3)
To find the zeroes:
x^2-x-3=0
x^2-x =3
x^2-x+ 1/4=3+ 1/4 complete the square by taking 1/2 the middle term and squaring it.
(x- 1/2)^2=13/4
x- 1/2=+-sqrt(13)/2 sqrt of each side.
x=1/2+-sqrt(13)/2
x=(1+sqrt(13))/2, (1-sqrt(13))/2
.
The 2 places the graph crosses the x axis (the x intercepts[where y=0]) also give the answer.
You could also use the quadratic equation.
Ed
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