SOLUTION: I’m not sure if I have determined the correct value. Could you please check my answer? (The symbol of a long slim S comes first) (4/x) dx over intervals (1, 3) = 4 Is

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Question 127174: I’m not sure if I have determined the correct value. Could you please check my answer?
(The symbol of a long slim S comes first) (4/x) dx over intervals (1, 3) = 4 Is that correct or did I miss something? Thank you
Also, would this formula (the symbol of a long slim S) e^x dx be completed at e^x or do I need to go farther?
Thank you so much for your help again. You folks are awesome!

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
The symbol of a long slim S comes first) (4/x) dx over intervals (1, 3) = 4 Is that correct or did I miss something? Thank you
Also, would this formula (the symbol of a long slim S) e^x dx be completed at e^x or do I need to go farther?
----------------------
That "long slim S" is an integral sign.
------
int(4/x)dx evaluated from x=1 to x=3 is
4lnx evaluated at x=3 - 4lnx evaluated at x=1
You get: 4ln3-4ln1= 4(ln3-ln1) = 4(ln3-0) = 4ln3 = 4.3944...
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int(e^x) = e^x + C, where C is any constant.
You need the +C because your problem is an
indefinate integral.
===============
Cheers,
stan H.

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