SOLUTION: Determine as coordenadas da vértice na parábola da função f(x) = x² - 10x + 25

Algebra.Com
Question 1209296: Determine as coordenadas da vértice na parábola da função f(x) = x² - 10x + 25
Answer by ikleyn(52879)   (Show Source): You can put this solution on YOUR website!
.

This parabola equation is

    f(x) = x^2 - 10x + 25.


It can be written in this equivalent form

    f(x) = .


This is a vertex form of the parabola, and it says that the vertex point is  

    (x,y)_vertex = (5,0).    ANSWER

Solved.



RELATED QUESTIONS

Determine as coordenadas da vértice na parábola da função f(x) = x²-10x +... (answered by ikleyn)
Determine as coordenadas da vértice na parábola da função f(x) = x² -10x +... (answered by ikleyn)
Da (answered by solver91311)
Ref. Questions 1043754, 1043749: d(a + x) - b(c - x) = da da + dx - bc + bx = da (answered by josgarithmetic)
wats da square root of... (answered by rapaljer)
24cm -... (answered by math-vortex)
Gostaria de calcular a função f(x + 3) = x2 - 4 quanto vale f(f(5)). obrigado,... (answered by Edwin McCravy)
if there is an right angle and a side is 15 while b side is 25 how can i get da value of... (answered by richwmiller)
Rectangle ABCD Given: AB = 2x + 8 BC = 4x + 2 CD = 3x + 4 Find: x and... (answered by Alan3354)