SOLUTION: American Jackie Joyner-Kersee set the Olympic Long Jump women's record in Seoul, South Korea in 1988.
Her record jump can be modeled by the following quadratic equation (with x
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Question 1199197: American Jackie Joyner-Kersee set the Olympic Long Jump women's record in Seoul, South Korea in 1988.
Her record jump can be modeled by the following quadratic equation (with x representing length and y representing height):
y = -.014x² + .34x
How high was she at her highest point, and how far did she jump, respectively?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
American Jackie Joyner-Kersee set the Olympic Long Jump women's record in Seoul, South Korea in 1988.
Her record jump can be modeled by the following quadratic equation (with x representing length and y representing height):
y = -.014x² + .34x
How high was she at her highest point, and how far did she jump, respectively?
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It's a parabola, so the v/ertex is max height at x = -b/2a
-b/2a = -0.34/(-0.028) = 85/7
y = -0.014*(85/7)^2 + 0.34*85/7 = ~2.0643 (no units given)
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The distance is at touchdown, when y = 0
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y = -.014x² + .34x = 0
x = 0 at the start
x = 0.34/0.014 = ~ 24.2857 inches? feet?
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"respectively" is superfluous, has no meaning in the statement.
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This is how it should read:
Her record jump can be modeled by the following quadratic equation, with x and y representing length and height, respectively
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