SOLUTION: Please help me. {{{2x^4-5x^3-17x^2+41x-21=0}}}

Question 119632: Please help me.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2x^4-5x^3-17x^2+41x-21=0
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I graphed it and found a zero at x=-3 and a double zero at x = 1
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Using synthetic find the 4th zero:
-3)....2....-5....-17....41....-21
........2.....-11...16....-7....|..0
1).......2......-9....7....|..0
1)........2.......-7...|..0
Final Quotient: 2x-7
Final zero: x = 7/2
=========================
Zeroes: -3,1,1,7/2
=========================
Cheers,
Stan H.

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