SOLUTION: Consider g(x) = 2x^3 - x^2 + 2x -1 (a) Tell the maximum number of real zeros that the function may have. Do not attempt to find the zeros. (b) List the potential rational

Algebra.Com
Question 1189362: Consider g(x) = 2x^3 - x^2 + 2x -1
(a) Tell the maximum number of real zeros that the function may have. Do not
attempt to find the zeros.
(b) List the potential rational zeros. Do not attempt to find the zeros.
(c) Determine the real zeros of g and write g in factored form.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


(a) A polynomial of degree n has a maximum of n real zeros. This polynomial is degree 3, so the maximum number of real zeros is 3.

(b) (+/-) (p/q), where p is a factor of the constant term (-1) and q is a factor of the leading coefficient (2). So the possible rational zeros are
1, -1, 1/2, and -1/2.

(c)

The coefficients 2, -1, 2, -1 show us this can easily be factored by grouping:





The factor (x^2+1) produces a pair of complex roots. The only real root is 1/2, coming from the factor (2x-1).


RELATED QUESTIONS

Consider g(x)=3x^3-2x^2+x+2 a)Tell the maximum number of real zeros that the function... (answered by Edwin McCravy,ikleyn)
List all of the potential rational zeros of the polynomial function. Do not attempt to... (answered by fractalier)
Use Descartes rule of signs to determine how many positive and how many negative real... (answered by mukhopadhyay)
Consider the following. f(x)=1/2x^2+3/2x-1/2 (a) Find all the real zeros of... (answered by ReadingBoosters)
Find all real zeros of the function:... (answered by Positive_EV)
For the function find the maximum number of real zeros that the function can have, the... (answered by nerdybill)
Hello, I need help with roots and zeros. I don't understand how to find the number of... (answered by stanbon)
Please help w/ the following: Using Descartes Rule of Signs to determine how many... (answered by venugopalramana)
5. For the following function: f(x)=x^6-7x^4-2x+7 (A)Find the maximum number of real... (answered by stanbon)