SOLUTION: There Is Two Problems First one The graph of which equation is Straight line parallel to the graph of Y=2x? And Second one is An equation Of the line that Contains the orig

Algebra ->  Rational-functions -> SOLUTION: There Is Two Problems First one The graph of which equation is Straight line parallel to the graph of Y=2x? And Second one is An equation Of the line that Contains the orig      Log On


   



Question 118103: There Is Two Problems First one
The graph of which equation is Straight line parallel to the graph of Y=2x?
And Second one is
An equation Of the line that Contains the origin and the Point (1,2)
Can U plz Send me answer to This Question

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
#1

Anything parallel to y=2x will have a slope of 2. So just add any number (I'm going to add 2) to y=2x to get y=2x%2B2

Notice if we graph y=2x and y=2x%2B2 we can see that the two lines are parallel. So this visually verifies our answer.

+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+2x%2C2x%2B2%29+ Graph of y=2x (red) and y=2x%2B2 (green)





#2

Remember the origin is the point (0,0)


First lets find the slope through the points (0,0) and (1,2)

m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula (note: is the first point (0,0) and is the second point (1,2))

m=%282-0%29%2F%281-0%29 Plug in y%5B2%5D=2,y%5B1%5D=0,x%5B2%5D=1,x%5B1%5D=0 (these are the coordinates of given points)

m=+2%2F1 Subtract the terms in the numerator 2-0 to get 2. Subtract the terms in the denominator 1-0 to get 1


m=2 Reduce

So the slope is
m=2

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Now let's use the point-slope formula to find the equation of the line:



------Point-Slope Formula------
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

y-0=%282%29%28x-0%29 Plug in m=2, x%5B1%5D=0, and y%5B1%5D=0 (these values are given)


y-0=2x%2B%282%29%280%29 Distribute 2

y-0=2x%2B0 Multiply 2 and 0 to get 0.

y=2x%2B0%2B0 Add 0 to both sides to isolate y

y=2x%2B0 Combine like terms 0 and 0 to get 0
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Answer:


So the equation of the line which goes through the points (0,0) and (1,2) is:y=2x%2B0

The equation is now in y=mx%2Bb form (which is slope-intercept form) where the slope is m=2 and the y-intercept is b=0

Notice if we graph the equation y=2x%2B0 and plot the points (0,0) and (1,2), we get this: (note: if you need help with graphing, check out this solver)

Graph of y=2x%2B0 through the points (0,0) and (1,2)

Notice how the two points lie on the line. This graphically verifies our answer.