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What is the cubed root of (X^6*Y^4)/2
Thank you so much!
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Question 117927: Do you have the time to help?
What is the cubed root of (X^6*Y^4)/2
Thank you so much!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the cubed root of (X^6*Y^4)/2
--------------------------------------------------
I'm going to assume you are taking the cube root of the entire
expression:
= cubrt(x^6*y^4/2)
To rationalize the denominator, multiply numerator and
denominator by "4"
= cubrt(4x^6y^4/8)
Separate the perfect cube factors from those that are not
perfect cubes:
= cubrt(x^6*y^3/8)*cubrt(4y)
Take the cube root of the perfect cube factors:
= (1/2)x^2 y * cubrt(4y)
===================
Cheers,
Stan H.
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