SOLUTION: A triangular garden has two equal sides 3.6 m long and a contained angle of 80°. Draw and label a diagram. a) How much fencing, to the nearest metre, is needed for this garden?

Question 1173353: A triangular garden has two equal sides 3.6 m long and a contained angle of 80°. Draw and
label a diagram.
a) How much fencing, to the nearest metre, is needed for this garden?
b) How much area does the garden cover? Round your answer to the nearest tenth of a square metre
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

After sketching a line down representing the height of the isosceles Triangle,

dividing the triangle equally, following applies per sketch of left half

hypotenuse = 3.6m

Angle A = 90° - 80°/2 =50°

cos50° = adj/hyp =b/2.6 ( b= B/2)  and  sin50° =opp/hyp= height/2.6 

b = 2.6cos50° = 1.7m   = 3.4m   and height = 2.6sin50° = 1.99 m

a) amount of fencing = 2.6m +2.6m + 3.4m 

b) Area = (3.4m)(1.99m)/2 



 

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